Question

nt. The drug amount in the body dose of a drug is iniected into the body of a patient. The drug amount in me buy decreases at the rate of 11% per hour, that is, A = -0.11A where A is the amount in the body and t is the time, in hours. a. (3 pts.) A dose of 4 cubic centimeters (ce) is administered. Assuming Ao - the function that satisfies the equation. b. (2 pts.) How much of the initial dose of 4 cc will remain after 1.5 hours? Round to the nearest cubic centimeter. c. (5 pts.) After how long does half of the original dose remain? Round to the nearest tenth of an hour. SHOW WORK!!!

Answer 1

ACCESANDAL EN dA = -0011 A dA = -couldt. By integrating -ollt tc e =-oolt to Act) = | Act)= eonnt cho @ Given atto, A(O)= Ao=4 they implis 4a eic [c=4 TA4420th @ o at t= 105 hrs Act)= ? from @ we have AC) 4.25*11x15 *148el 3:3956)<c 0.16 when Alt) = 422 cc then ta? from @ we have &=40llt eltų - allt= log(e) Is son wit moll log Co.s) = 16.3 hrs] CamScanner