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At each point on the surface of the cube the electric field is parallel to the...

At each point on the surface of the cube the electric field is parallel to the z axis. The length of each edge of the cube is 3.7 m. On the top face of the cube the electric field - 33 k N/C and on the bottom face it is + 22 k N/C. Determine the net charge contained within the cube.

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Answer #1


flux through the top face phi 1= B1*A = 33*10^3*3.7^2 = 451770 Nm^2/C


flux through the bottom face phi 2 = B2*A = 22*10^3*3.7^2 = 301180 Nm^2/C


flux through front , back , left , right faces = 0

total flux = phi = 451770 + 301180 = 752950 Nm^2/C

from gauss law

total flux = Qin/eo

Qin = 752950*8.84*10^-12 = 6.7*10^-6 C

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