Question

1. A compound of formula C-H3O shows 'H NMR signals at 2.3 8 (singlet 2H), and 7.3 8 (singlet with some splitting, 5H). The infrared spectrum shows as broad absorption between 3200 and 3500 cm and strong narrow absorbances at 306 1030 cm! Write the structure of the compound and provide an acceptable name. (10 te AR signals at 2.3 8 (singlet, 11), 4.6 8 (singlet, frared spectrum shows a strong and

Answer 1

The molecular formula of the compound is C₇H₈O.

The compound may be benzyl alcohol.

The detail explaination is shown below.

of the compound o the molecular formula is - Cf Hego. Double bond equivalent of the compound DBE - Att - As, Catboc DBE = [tf+1) - 2/2] I OBE = Carl) - 6/2 - 4 since the formula is be too and DBE 2 4 This implies that there may be a benzene ping and there ie no other double douh bond than that of benzene ring. a from the 'H-NMR data it is evident that there are three types of Hatims. They are - lig 2.38 (singlet, 14). (11) toso ( singlet, 2H). sing rt.38 e singlet, SH). 7.38 (singlet, st) implies the atoms anociated trith benzene sing. 4.68 (singlet, 2H) implies the 2 tt atoms on the carbon atom attached with both benzene ping and anggen. 2.38 i implies the oth ato bonded [ hydrogen.

an and infrared spectrom, there is a strong broad absorption between 3200 and 3500 This and gen confirmed the presence of ont bond the broadness is due to the hydew bondin It is due to oru bonded etty & atoms the Habonding the t can not comple with of retty group. Again there is characterstie peaks eac caromatice - 2875 cane. -e-ul aromate) - 3085 und co - 1030 unt. Then the structure of the compound t CH₂-OH (Berzugl alcohol).