Question

. (5.33) The toco toucan, the largest member of the toucan family, possesses the largest beak relative to body size of all birds. This exaggerated toature has received various interpretations, such as being a refined adaptation for feeding. However, the large surface area thay also be an important mechanism for radiating heat and hence cooling the bird) as outdoor temperature increases. Here are data for beak heat loss, as a percent of total body heat loss, at various temperatures bry degrees Celsius. Temperaturel °C) 30 29 28 27 26 25 24 23 نے 21 20 19 18 17 16 15 60 61 57 56 55 513 4 53 56 ;4 37 3 37 36 35 با نا !Trcert heat 15 fror The equation of the least squares regression line for predicting beak heat loss, as a percent of total body heat loss from all sources, from temperature is (Use decimal notation. Give your answer to four decimal places.) Use the equation to predict ( 0.01) beak heat loss, as a percent of total body heat loss from all sources, at a temperature of 25 degrees Celsius. 19 What percent (+ 0.01) of the variation in beak heat loss is explained by the straight-line relationship with temperature? Find the correlation (0.001) between beak heat loss and temperature: ۳ - eBook Hint Check Syriax 15. A study was conducted on horses to identify factors that might contribute to the formation of enteroliths, stones that form in the colon of the horse and eventually lead to blockage and death the table below summan disease status by sex (gelding, mare and stallion). Romaining: 4:28:00 Start: 7:16 PM Type here to search BANG & OLUFSEN hackspace اااااااالالالالالالالالالالال اااااااااااااال

Answer 1

X-MX Y- My (X- M, л Մ 56.25 42.25 л л Ծ л Ծ л Պ ա л л զ л Տ & Ա : m e am © sq m + n = (X - MF)(Y- M.,) 111.0938 76.7813 59.4688 62.1563 37.8438 | 2.0313 -12.2013 -2.5938 -1.9063 4.7813 -12.0313 25.1563 45.8438 50.5313 105.2188 91.4063 -14.8125 -11.8125 -10.8125 -13.8125 -10.8125 -0.8125 8.1875 5.1875 -3.8125 3.1875 -4.8125 .1875 10.1875 9.1875 16.1875 12.1875 Փ л Մ Մ Մ Մ Մ Մ Մ NNNNNNNNNNNNNNN Մ Մ Մ Մ Մ Մ Մ Մ Փ л 2.25 л Փ л * л Փ Փ л * л SS: 340 SP։ 643.5

Sum of X = 360
Sum of Y = 765
Mean X = 22.5
Mean Y = 47.8125
Sum of squares (SS_X) = 340
Sum of products (SP) = 643.5

Regression Equation = ŷ = bX + a

b = SP/SS_X = 643.5/340 = 1.8927

a = M_Y - bM_X = 47.81 - (1.89*22.5) = 5.2279

ŷ = 1.8927X + 5.2279

Now for X=25, ŷ = (1.8927*25) + 5.2279=52.5454

X-MX Y - My - 14.812 -11.812 - 10.812 - 13.812 - 10.812 -0.812 090 00 00 -7.500 -6.500 -5.500 -4.500 -3.500 -2.500 -1.500 -0.500 0.500 1.500 2.500 3.500 4.500 5.500 6.500 7.500 wwu o (X-MX2 56.250 42.250 30.250 20.250 12.250 6.250 2.250 0.250 0.250 2.250 6.250 12.250 20.250 30.250 42.250 56.250 (Y - M.)2 219.410 139.535 116.910 190.785 116.910 0.660 67.035 26.910 14.535 10.160 23.160 51.660 103.785 84.410 262.035 148.535 (X-MXNY - M) 111.094 76.781 59.469 62.156 37.844 2.031 - 12.281 -2.594 -1.996 4.781 - 12.031 25.156 45.844 50.531 105.219 91.406 00 CO o 00 00 00 00 co 16.188 12.188 Mx: 22.500 My: 47.812 Sum: 340.000 Sum: 1576.438 Sum: 643.500

X Values
∑ = 360
Mean = 22.5
∑(X - M_x)² = SS_x = 340

Y Values
∑ = 765
Mean = 47.812
∑(Y - M_y)² = SS_y = 1576.438

X and Y Combined
N = 16
∑(X - M_x)(Y - M_y) = 643.5

R Calculation
r = ∑((X - M_y)(Y - M_x)) / √((SS_x)(SS_y))

r = 643.5 / √((340)(1576.438)) = 0.879

So r^2=0.7726, hence 77.26% of variation in y is explained by x

As already computed r=0.879