A shotput thrower releases the shot with a release speed of 15m/s and a release angle...
A shotput thrower releases the shot with a release speed of 15m/s and a release angle of 42° above the horizontal. The initial height that the thrower releases the shot is 2 m. In all the problems, neglect the effect of air resistance.
1. What is the maximum height reached by the shot (relative to the ground)?
2. How long is the shot in the air for?
3. How far does the shot travel horizontally?
4. What is the vertical velocity just before the shot lands on the ground?
5. If you were to coach this shotput thrower, would you advise him to throw at a 45° release angle to increase his distance? Why or why not?
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A shotput thrower releases the shot with a release speed of
15m/s and a release angle...
In the Olympic shotput event, an athlete throws the shot with an initial speed of 13.0...
In the Olympic shotput event, an athlete throws the shot with an initial speed of 13.0 m/s at a 43.0 ∘ angle from the horizontal. The shot leaves her hand at a height of 1.80 m above the ground. How far does the shot travel?
In the Olympic shotput event, an athlete throws the shot with an initial speed of 13.0...
In the Olympic shotput event, an athlete throws the shot with an initial speed of 13.0 m/s at a 43.0 ∘angle from the horizontal. The shot leaves her hand at a height of 1.80 m above the ground. How far does the shot travel? Express your answer with the appropriate units. IT IS NOT 22.4m PLEASE DON'T COMMENT IT LIKE THE LAST PERSON. THANK YOU!!!
Review Part A In the Olympic shotput event, an athlete throws the shot with an initial...
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Review Part A In the Olympic shotput event, an athlete throws the shot with an initial speed of 13.0 m/s at a 47.0° angle from the horizontal. The shot leaves her hand at a height of 1.80 m above the ground. How far does the shot travel? Express your answer with the appropriate units. LA Value 山 = | Units Submit Previous Answers Request Answer
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