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Consider the equilibrium between PCls, PClj and Cl2. PCIs(g)-PC13(g) + Cl2(g) K 0.251 at 571 K...
For the equilibrium reaction: PCis(g) = PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration...
For the equilibrium reaction: PCis(g) = PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibrium equation for the reaction. [1 mark] b. If 2.0 gram of PCis(g) is introduced into a 1.5 L flask what will be the equilibrium concentrations of PCls, PC13 and Cl2? [4marks]
Consider the equilibrium between COCl2, CO and Cl2. COCl2(g) CO(g) + Cl2(g) K = 0.112 at...
Consider the equilibrium between COCl2, CO and Cl2. COCl2(g) CO(g) + Cl2(g) K = 0.112 at 904 K The reaction is allowed to reach equilibrium in a 7.00-L flask. At equilibrium, [COCl2] = 0.258 M, [CO] = 0.170 M and [Cl2] = 0.170 M. (a) The equilibrium mixture is transferred to a 14.0-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a...
Consider the equilibrium between SO2Cl2, SO2 and Cl2. SO2Cl2(g) <-->SO2(g) + Cl2(g) K = 0.552 at...
Consider the equilibrium between SO2Cl2, SO2 and Cl2. SO2Cl2(g) <-->SO2(g) + Cl2(g) K = 0.552 at 412 K The reaction is allowed to reach equilibrium in a 6.30-L flask. At equilibrium, [SO2Cl2] = 0.142 M, [SO2] = 0.279 M and [Cl2] = 0.279 M. (a) The equilibrium mixture is transferred to a 12.6-L flask. In which direction will the reaction proceed to reach equilibrium? _________to the rightto the left (b) Calculate the new equilibrium concentrations that result when the equilibrium...
ampere The reaction, PCls (g) 5 PC13(g) + Cl2(g), has Kc = 4.20 x 102. If...
ampere The reaction, PCls (g) 5 PC13(g) + Cl2(g), has Kc = 4.20 x 102. If 0.1050 mol of PCL5, 0.0450 mol of Cl2 and 0.0450 mol of PCl3 is placed in a 0.5000-L flask at 250°C, what are the equilibrium concentrations of PCl3 and Cl, if equilibrium (PCI5] = 0.2065 M? A) [PC13] = 0.00350 M; (Cl2] = 0.00350 M B) [PC13] = 0.0900 M; [Cl2] = 0.0900 M -=51,85 (66450) (19450) C) [PC13] = 0.2100 M; [Cl2] =...
Answer the questions about the following reaction below. The equilibrium constant for the decomposition of PCls...
Answer the questions about the following reaction below. The equilibrium constant for the decomposition of PCls at 250°C is 0.041 ΔH is positive; reactants and products are gases at 250°C. Refer to your textbook. 1. Is the reaction above exothermic or endothermic? 2. What happens to the concentrations of PCls and Cl if more PCls is added once the reaction reaches equilibrium? (increases, decreases) PC1s Cl2 3. What happens to the moles of PCIs, PCls and Cl in the container...
Part B please For the equilibrium reaction: PCI (g) =PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibr...
Part B please
For the equilibrium reaction: PCI (g) =PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibrium equation for the reaction. [1 mark] b. If 2.0 gram of PCis(g) is introduced into a 1.5 L flask what will be the equilibrium concentrations of PCls, PClz and Cl ? [4marks]
Consider the equilibrium between COBr2, CO and Br2 COBr2(g) at 382 K CO(g) + Brz(9) K=...
Consider the equilibrium between COBr2, CO and Br2 COBr2(g) at 382 K CO(g) + Brz(9) K= 2.08 The reaction is allowed to reach equilibrium in a 13.8-L flask. At equilibrium, [COBr2] = 4.43x10-2 M, [CO] = 0.304 M and [Br2] = 0.304 M. (a) The equilibrium mixture is transferred to a 6.90-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 6.90-L...
Consider the reaction. PC15(g) 근 PC13(g) + Cl2(g) K = 0.042 The concentrations of the products...
Consider the reaction. PC15(g) 근 PC13(g) + Cl2(g) K = 0.042 The concentrations of the products at equilibrium are PC, l = 0 10 M and [CI| = O. 1 3 M What is the concentration of the reactant, PCl, at equilibrium? PCI,I
Consider the equilibrium between COBr2, CO and Br2. COBr2(g) CO(g) + Br2(g) K = 0.254 at...
Consider the equilibrium between
COBr2, CO and
Br2.
COBr2(g) CO(g)
+ Br2(g) K = 0.254 at
350 K
The reaction is allowed to reach equilibrium in a
6.40-L flask. At equilibrium,
[COBr2] = 0.294 M,
[CO] = 0.274 M and
[Br2] = 0.274 M.
(a) The equilibrium mixture is transferred to a
12.8-L flask. In which direction will the reaction
proceed to reach equilibrium?
(b) Calculate the new equilibrium concentrations that result when
the equilibrium mixture is transferred to a...
Consider the equilibrium between COBr2, CO and Br2. COBr2(g) -->CO(g) + Br2(g) K = 1.84 at...
Consider the equilibrium between COBr2, CO and Br2. COBr2(g) -->CO(g) + Br2(g) K = 1.84 at 380 K The reaction is allowed to reach equilibrium in a 13.8-L flask. At equilibrium, [COBr2] = 3.02×10-2 M, [CO] = 0.236 M and [Br2] = 0.236 M. (a) The equilibrium mixture is transferred to a 6.90-L flask. In which direction will the reaction proceed to reach equilibrium? _________to the right? to the left? (b) Calculate the new equilibrium concentrations that result when the...
For the equilibrium reaction: PCis(g) = PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibrium equation for the reaction. [1 mark] b. If 2.0 gram of PCis(g) is introduced into a 1.5 L flask what will be the equilibrium concentrations of PCls, PC13 and Cl2? [4marks]
ampere The reaction, PCls (g) 5 PC13(g) + Cl2(g), has Kc = 4.20 x 102. If 0.1050 mol of PCL5, 0.0450 mol of Cl2 and 0.0450 mol of PCl3 is placed in a 0.5000-L flask at 250°C, what are the equilibrium concentrations of PCl3 and Cl, if equilibrium (PCI5] = 0.2065 M? A) [PC13] = 0.00350 M; (Cl2] = 0.00350 M B) [PC13] = 0.0900 M; [Cl2] = 0.0900 M -=51,85 (66450) (19450) C) [PC13] = 0.2100 M; [Cl2] =...
Answer the questions about the following reaction below. The equilibrium constant for the decomposition of PCls at 250°C is 0.041 ΔH is positive; reactants and products are gases at 250°C. Refer to your textbook. 1. Is the reaction above exothermic or endothermic? 2. What happens to the concentrations of PCls and Cl if more PCls is added once the reaction reaches equilibrium? (increases, decreases) PC1s Cl2 3. What happens to the moles of PCIs, PCls and Cl in the container...
Part B please
For the equilibrium reaction: PCI (g) =PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibrium equation for the reaction. [1 mark] b. If 2.0 gram of PCis(g) is introduced into a 1.5 L flask what will be the equilibrium concentrations of PCls, PClz and Cl ? [4marks]
Consider the equilibrium between COBr2, CO and Br2 COBr2(g) at 382 K CO(g) + Brz(9) K= 2.08 The reaction is allowed to reach equilibrium in a 13.8-L flask. At equilibrium, [COBr2] = 4.43x10-2 M, [CO] = 0.304 M and [Br2] = 0.304 M. (a) The equilibrium mixture is transferred to a 6.90-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 6.90-L...
Consider the reaction. PC15(g) 근 PC13(g) + Cl2(g) K = 0.042 The concentrations of the products at equilibrium are PC, l = 0 10 M and [CI| = O. 1 3 M What is the concentration of the reactant, PCl, at equilibrium? PCI,I
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