Consider the reaction. PC15(g) 근 PC13(g) + Cl2(g) K = 0.042 The concentrations of the products...
Consider the reaction. PC1=(8) =PC13(e) + Cl2(g) K = 0.042 The concentrations of the products at equilibrium are PCI -0.24 M and (C1) = 0.10 M. What is the concentration of the reactant, PCIe, at equilibrium? [PC1,) = |
Consider the reaction. PCI (6) PCI,(9) + CIB) K = 0.042 The concentrations of the products at equilibrium are (PCII = 0.27 M and ICI,l = 0.10 M. What is the concentration of the reactant, PCs, at equilibrium? IPCI1 = M
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC15(g) Calculate the equilibrium concentrations of reactant and products when 0.389 moles of PC13 and 0.389 moles of Cl2 are introduced into a 1.00 L vessel at 500 K [PC13] = [Cl] = [PC15] - The equilibrium constant, Kc, for the following reaction is 5.10x10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibrium concentration of HCl when 0.467 moles of NHACI(S)...
Consider the reaction. PCI; (g) = PCI,(g) + Cl2(g) Kc = 0.0420 The concentrations of the products at equilibrium are [PC13] = 0.160 M and [Cl2] = 0.160 M. What is the concentration of the reactant, PCs, at equilibrium? [PCI31= C [PCIS] = M
The equilibrium constant, K, for the following reaction is 5.56×10 2 at 541 K. PC13(g) PC13(e) + Cly(8) An equilibrium mixture of the three gases in a 13.5 L container at 541 K contains 0.245 M PCI, 0.117 M PC13 and 0.117 M CI, What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 6.44 L? M [PC15] = [PC13] = [CI] M...
The equilibrium constant, K., for the following reaction is 1.20 10-2 at 500 K. PCI(8) =PC13(g) + Cl2(g) Calculate the equilibrium concentrations of reactant and products when 0.363 moles of PC13() are introduced into a 1.00 L vessel at 500 K M [PC131 = [PC13] - [Cl] M M
The equilibrium constant, K, for the following reaction is 1.20x10-2 at 500 K. PC15(E) =PC13(E) + Cl2(E) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.157 M PCI3, 4.34x102 MPC12 and 4.34x102 M CI, What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.17x10 - mol of Cl2(g) is added to the flask? [PC13] = [PC13] = [Cl] =
Consider the reaction. PCl (g)PC3(g) + Cl2(g) Ke = 0.0420 The concentrations of the products at equilibrium are [PCl3] = 0.200 M and [Cl2] = 0.190 M. What is the concentration of the reactant, PCI5, at equilibrium? PCI5 M
Consider the equilibrium between PCls, PClj and Cl2. PCIs(g)-PC13(g) + Cl2(g) K 0.251 at 571 K The reaction is allowed to reach equilibrium in a 15.2-L flask. At equilibrium, [PCIs]-9.75x102 M, [PCl,]-o.156 M and [C12] = 0.156 M. (a) The equilibrium mixture is transferred to a 7.60-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 7.60-L flask. [PCI5] [C12] =
The equilibrium constant, K, for the following reaction is 3.52*10 at 528 K PC13(g) =PC12(g) + Cl2(g) An equilibrium mixture of the three gases in a 9.42 L container at 528 K contains 0.244 M PCIE. 9.27X10-2M PCI, and 9.27-10-2M Cly. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 17.1 L? M [PC15] [PC13] = [Cl] M M