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Consider the reaction. PCl (g)PC3(g) + Cl2(g) Ke = 0.0420 The concentrations of the products at...
Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g)?c=0.0420 PCl 5 ( g ) ↽ − − ⇀ PCl 3 ( g ) + Cl 2 ( g ) K c = 0.0420 The concentrations of the products at equilibrium are [PCl3]=0.270 M [ PCl 3 ] = 0.270 M and [Cl2]=0.180 M [ Cl 2 ] = 0.180 M . What is the concentration of the reactant, PCl5 PCl 5 , at equilibrium? [PCl5]= [ PCl 5 ] =
Consider the reaction. PCl5(g)−⇀↽−PCl3(g)+Cl2(g)Kc=0.0420 The concentrations of the products at equilibrium are [PCl3]=0.180 M and [Cl2]=0.280 M. What is the concentration of the reactant, PCl5, at equilibrium?
Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g)?c=0.0420 The concentrations of the products at equilibrium are [PCl3]=0.120 M and [Cl2]=0.150 M. What is the concentration of the reactant, PCl5, at equilibrium?
Consider the reaction. PCI; (g) = PCI,(g) + Cl2(g) Kc = 0.0420 The concentrations of the products at equilibrium are [PC13] = 0.160 M and [Cl2] = 0.160 M. What is the concentration of the reactant, PCs, at equilibrium? [PCI31= C [PCIS] = M
Consider the reaction. PC15(g) 근 PC13(g) + Cl2(g) K = 0.042 The concentrations of the products at equilibrium are PC, l = 0 10 M and [CI| = O. 1 3 M What is the concentration of the reactant, PCl, at equilibrium? PCI,I
Consider the reaction. PC1=(8) =PC13(e) + Cl2(g) K = 0.042 The concentrations of the products at equilibrium are PCI -0.24 M and (C1) = 0.10 M. What is the concentration of the reactant, PCIe, at equilibrium? [PC1,) = |
Consider the reaction. PCI (B) = PCI (8) + Cl (8) K = 0.0420 The concentrations of the products at equilibrium arc (PCI) = 0.230 M und Chl = 0.270 M. What is the concentration of the reactant, PCs, at equilibrium? IPCISI M
< Question 3 of 11 > Consider the reaction. PCI,(g) =PCI,(g) + CI,(g) K = 0.0420 The concentrations of the products at equilibrium are [PC13) = 0.130 M and [Cl] = 0.140 M. What is the reactant, PCls, at equilibrium? (PCI) = C [PC1s] = M
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCl3(g) + Cl2(g) = PCl5(g) Calculate the equilibrium concentrations of reactant and products when 0.249 moles of PCl3 and 0.249 moles of Cl2 are introduced into a 1.00 L vessel at 500 K. [PCl3] = M [Cl2] = M [PCl5] = M The equilibrium constant, Kc, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) = H2(g) + I2(g) Calculate the equilibrium concentrations of reactant and...
Consider the equilibrium between PCls, PClj and Cl2. PCIs(g)-PC13(g) + Cl2(g) K 0.251 at 571 K The reaction is allowed to reach equilibrium in a 15.2-L flask. At equilibrium, [PCIs]-9.75x102 M, [PCl,]-o.156 M and [C12] = 0.156 M. (a) The equilibrium mixture is transferred to a 7.60-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 7.60-L flask. [PCI5] [C12] =