Urn A contains four white balls and six black balls. Urn B contains three white balls and seven black balls. A ball is drawn from Urn A and then transferred to Urn B. A ball is then drawn from Urn B. What is the probability that the transferred ball was black given that the second ball drawn was black? (Round your answer to three decimal places.)
Homework Answers
P(second ball was black)=P(transferred ball was black and second ball was black)+P(transferred ball was white and second ball was black)=(6/10)*(8/11)+(4/10)*(7/11)=0.6909
therefore probability that the transferred ball was black given that the second ball drawn was black
=P(transferred ball was black and second ball was black)/P(second ball was black)
==(6/10)*(8/11)/0.6909=0.632
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