An urn contains four red balls, six black balls, and five green balls. If two balls...

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An urn contains four red balls, six black balls, and five green balls. If two balls...

An urn contains four red balls, six black balls, and five green balls. If two balls are selected at random without replacement from the urn, what is the probability that a red ball and a black ball will be selected? (Round your answer to three decimal places.)

math Statistics-And-Probability

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Answer 1

Answer #1

Total balls = 4 + 6 + 5 = 15

P(red ball and black ball) = 4C1 * 6C1 / 15C2 = 4 * 6 / 105 = 0.229

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Answer 2

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