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Assume a member is selected at random from the population represented by the graph. Find the probability that the member sele
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Answer #1

Here, μ = 508, σ = 123, x1 = 200 and x2 = 400. We need to compute P(200<= X <= 400). The corresponding z-value is calculated using Central Limit Theorem

z = (x - μ)/σ
z1 = (200 - 508)/123 = -2.5
z2 = (400 - 508)/123 = -0.88

Therefore, we get
P(200 <= X <= 400) = P((400 - 508)/123) <= z <= (400 - 508)/123)
= P(-2.5 <= z <= -0.88) = P(z <= -0.88) - P(z <= -2.5)
= 0.1894 - 0.0062
= 0.1832

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