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SAT Critical Reading Scores Assume a member is selected at random from the population represented by the graph. Find the prob

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Answer #1

Given that, mean (μ) = 503 and standard deviation (\sigma) = 123

Using standard normal z-table we want to find, P(200 < X < 375)

Where, X ~ Normal (503, 123)

\\ P(200 < X < 375) \\\\ = P(\frac { 200-503}{123} < \frac { X -\mu}{\sigma} < \frac { 375-503}{123}) \\\\ = P(-2.46 < Z < -1.04) \\\\ = P(Z < -1.04) - P(Z < -2.46) \\\\ = 0.1492 - 0.0069 \\\\ = 0.1423

Therefore, required probability is 0.1423

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