Question

il the instant 0 = 60°, the slotted guide rod is moving to the left with an acceleration of 2 m/s2 and a velocity of 5 m/s. Determine the angular accelera angular velocity of link AB at this instant. v = 5 m/s a = 2 m/s2 200 mm

Answer 1

Answer :-

Given that

The instant $\theta$ = 60 ⁰

The velocity = 5 m / s

Given dingram is V: Sms a: 2m/s 2.00mm -The tangential velocity s where w: The argalar velocity 8: The Tadiws Vt LU : "The vertical Component of VE y whexe Vy = 5m sin6o - 5.77m/s iv:5-77m/s 5.77 0.2 - 28. 87 Yad s The acclesation of slotted guids equal to the vertical component of acclevation of point A of link AB
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Ver *The vadial acc leratlon s a, : coso The verlical component i arv= ary: (5.77 Cos66° 0.2- 83.23 m/s" : 83-23 m/s To thy , we add vertical component Of tangen tial accleration ant at atv= aysine O Adding there two we get a: arytatv a = 83. 23 +aysfne =) 2 =83.23+alo.173) a = -469.su m/gu 1.:a:-u69.54m{s