Question

Calculate the value of K_p for the equation C(s) + CO_2(g) 2CO(g) K_p = ? given that at a certain temperature C(s) + 2H_2O(g) CO_2(g) + 2H_2(g) K_p^1 = 3.75 H_2(g) + CO_2(g) H_2O(g) + CO(g) K_p^2 = 0.701 K_p =

Answer 1

Step: 1: write the first equation as it is C + 2H2O--> CO2 + 2H2 Kp1 = 3.75 Step2: multiply the equation by 2 and we will get 2 H2+ 2 CO2 -> 2 H20+2 CO Kp2 2*0.701-1.402 By cancelling the equal terms on both sides, we will geet Кр-3.75+ 1.402-5.152 Therefore, Кр = 5.152

Answer 2

This is wrong. You multiply the K values when you add the two equations. 

Kpfinal = Kp₁(Kp₂)²

^{When you multiply a reaction by a factor, you have to raise your Kp value to that factor. So above, Kp}₂= 0.701²=0.4914

^{When you sum the two reaction equations, you have to multiply your two final Kp's.} 

^{Kp = (0.4914)(3.75) = 1.845}