Would a dihybrid cross between a heterozygous parent (BbSs) and a homozygous dominant parent (BBSS) end up as independently assorted genes? The results of offspring would be 100% dominant.
Answer -the dihybrid cross between heterozygous parent BbSs and homozygous dominant parent BBSS is as follows :
Parent genotype = BbSs. X. BBSS
BS | Bs | bS | bs | |
BS | BBSS | BBSs | BbSS | BbSs |
BS | BBSS | BBSs | BbSS | BbSs |
BS | BBSS | BBSs | BbSS | BbSs |
BS | BBSS | BBSs | BbSS | BbSs |
The genotype of offspring are as follows
BBSS : BBSs : BbSS :BbSs
4:4:4:4
From above explanation it is concluded that, this dihybrid cross would not end up as independently assorted genes.
Because the ratio for dihybrid cross for independent assortment of genes is 9:3:3:1
Therefore the ratio of genotypic characteristics does not match with 9:3:3:1.
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