1: The equation dy + 2y = xy-2 is an example of a Bernoulli equation. (a)...
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(1 point) A Bernoulli differential equation is one of the form dy + P()y= Q(Cy" (*) dr Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u=yl-n transforms the Bernoulli equation into the linear equation du dac + (1 - n)P(x)u= (1 - nQ(2). Consider the initial value problem xy' +y= -6xy?, y(1) = -2. (a) This differential equation can be written in the form...
Solve the Bernoulli equation a) xy′−4y = x^2√y, b) y′ = y(y^3 cosx +tgx), Solve the exact equation a) 2xcos^2 ydx +(2y−x2sin2y)dy = 0, b) (x^3 −3xy^2 +2)dx−(3x^2y−y^2)dy = 0, PLEASEEE it would mean a world to me
(1 point) A Bernoulli differential equation is one of the form dy dc + P(x)y= Q(x)y" Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u = yl-n transforms the Bernoulli equation into the linear equation du dr +(1 – n)P(x)u = (1 - nQ(x). Consider the initial value problem xy + y = 3xy’, y(1) = -8. (a) This differential equation can be written in the form (*)...
(15 points) A Bernoulli differential equation is one of the form dy dar + P(x)y= Q(x)y". Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u=yl-n transforms the Bernoulli equation into the linear equation du + (1 - n)P(x) = (1 - nQ(x). dx Use an appropriate substitution to solve the equation xy' +y=2xy? and find the solution that satisfies y(1) = 1.
1. Obtain the general solution to the equation dy (x2 + 2) ?+ xy - 3x = 0 dx
5.
Find the general solution of the Bernoulli equation
CO dy - y = e2xy3
An equation in the form
with
is called a Bernoulli equation and it can be solved using the
substitution
which transforms the Bernoulli equation into the following first
order linear equation for
:
Given the Bernoulli equation
we have
so
.
We obtain the equation
.
Solving the resulting first order linear equation for
we obtain the general solution (with arbitrary constant
) given by
Then transforming back into the variables
and
and using the initial condition
to find
....
Obtain the general solution to the equation. dy (x2+4) + xy - 3x = 0 dx The general solution is y(x) = ignoring lost solutions, if any.
Problem 5. (1 point) A Bernoulli differential equation is one of the form +P()y= Q()y" (*) Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u =y- transforms the Bemoulli equation into the linear equation + (1 - x)P(3)u = (1 - x)^(x). Consider the initial value problem ry' +y = -3.xy?, y(1) = 2. (a) This differential equation can be written in the form (*) with P(1) =...
for
differential equations
1. Identify each of the following differential equations as either Separable, Homogeneous, Linear Bernoulli, or Exact and solve the equation using the method of the type you have identified. Many can be classified in multiple ways, it is not necessary to list all possibilities. (3xy2 +2ycos x)+y'-y sin x-x =0 Туре: A. dx General Solution: B. (4xy+xy)2x+ xy2 dx Туре: General Solution: Туре: C. y'y'y+1 General Solution: (3x'y+e')-(2y-x-xe)dy Туре: D. dx General Solution: Туре: dy E. =y(xy-1)...