Question

Which of the below array initialization results in COMPILE TIME ERROR? int arr[2]={10,20,30); Oint arr[]={10,20,30); int arr[5]={10,20,30}; int arr[5]=1);

Answer 1

I uploaded the images with clear explanation about COMPILE TIME ERROR and RUN TIME ERRORS.And explained the solution with reasons for all option.

And solution for the given Question.

Answer: int arr[2]={10,20,30};(option 1)

All the other do not generate any compile time errors

Explanation:

performed cation Error: Error is an illegal coperation oppe by an user or developer . * It leads to abnormal behaviour of program Errors are mainly categorze ;) COMPILE TIME ERROR'S ii) RUNTIME ERROR'S into 2 types mainly categorized

i) Compile time Errors program a compile impiler fails to * Toompile time errors orefers to a state When compiler fails to .com * of occurs because of any syntax errors Eg: Missing parenthesis , illegal memory allocaton Cwrong or mistake allocation of memory) ete-- iv) RON TIME Erriors * These evrowers occur while executing the program. Cafter being compiled) * Eg; wrong input by user etc... will lead to runtime errors

Notes *These are futher categorized into many types like syntar eviors, legical evenors etc --- Given 1) int arr[2] = {10,20,30] * It is a invalid Intialization Here it an array with 3 integer values But we mentioned the size as a (Two). So leads to a compile time Error

*) imt arc] = 10,20,303 *H is a maild uintialization. Even though the size of away is not mentioned. The size is automatically taken by the number of elements in the array. 3) 1 int arris] : $10,20,30} * It is also voild intialization * The size of array is 5. But contain only 3 elements. # The remaining space may en contain garbage value on 0" ( zero int arr[s] = $10, 20, 30,0,0}

4) I int arx[5] = }; It is also valid intialization. * Here size is declared . But there are no elements in array. so option I) int arr[a] = {10,20,30] Will generate a compile time error

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