Question

Chapter 8, Section 2, Exercise 053 Peanut Butter vs Ham & Pickles The ANOVA table for...

Chapter 8, Section 2, Exercise 053

Peanut Butter vs Ham & Pickles

The ANOVA table for the SandwichAnts data below indicates that there is a difference in mean number of ants among the three types of sandwich fillings. We know that the difference is significant between vegimite and ham & pickles, but not between vegemite and peanut butter. What about peanut butter vs ham & pickles? Test whether the difference in mean ant count is significant (at a 5% level) between those two fillings, using the information from the ANOVA. Do a pairwise test of μ2 vs μ3, where μ2 is the mean ant count for peanut butter and μ3 is the mean ant count for ham & pickles. The sample means are x¯2=34.0 and x¯3=49.25.

Source DF SS MS F P
Filling 2 1561 781 5.63 0.011
Error 21 2913 138.7
Total 23 4474



A.

Find the test statistic.

Round your answer to two decimal places.

The test statistic is .

the absolute tolerance is +/-0.01

B.

Find the p-value.

Round your answer to three decimal places.

The p-value is .

the absolute tolerance is +/-0.001

C.

What is the conclusion of the test using a 5% significance level?

Reject H0.

Do not reject H0.

D.

Is there evidence of a difference in mean ant counts between peanut butter and ham & pickles?

Yes

No

0 0
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Answer #1

from the output given of one way anova analysis

we have

Source DF SS MS F P
Filling 2 1561 781 5.63 0.011
Error 21 2913 138.7
Total 23 4474


A )The test statistic is 5.63

B. The p-value is 0.011

C. since p value is less than 0.05 so we will reject H0

D. yes there is sufficient evidence of a difference in mean ant counts between peanut butter and ham & pickles

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