The voltage vi (t) in a network is defined by the equation dvi (f) dt2 Find...
Show the work to find T following the 3 steps please
Vi = Voe-tı/7 and at the second point you measured, the voltage and time would be: V2 = Voe-t2/7 T = You can combine these two equations and show that the time constant is: ta-ti In(Vi) - In(V2) Solve for the above equation of t using the two equations for (t1V) and (+2V2). In order to solve there are three things you need to do: 1. Divide the first...
Find vc(t) for t > 0 in the network in the accompanying figure using the step-by-step method. t=0 +9 V Please round all numbers to 3 significant digits. Click here to enter or edit your answer 7 vc(t) =
Use the node-voltage method to find the steady-state expression
for vo(t) in the circuit in (Figure 1) if
vg1= 19 sin(400t+143.13∘)V,
vg2= 18.03cos(400t+33.69∘)V.
Write the steady-state expression for vo(t) as vo=Vocos(ωt+ϕ),
where −180∘<ϕ≤180∘.
EE 211/EE 212 FA19 Circuits Analysis for Engineers KEE 211/212 HW #10 -- Impedances, Sinusoidal Steady State Analysis Problem 9.57 PSpicelMultisim Use the node-voltage method to find the steady-state expression for (t) in the circuit in (Figure 1) if gl19 sin(400t143.13°) V. g218.03 cos(400t 33.69o) V. Write...
please answer 1,2 and 3!
1. 2.
3.
Verify that the equation is an identity. (Hint: sin 2x = sin (x + x)) sin 2x = 2 sin x cOS X Substitute 2x = x + x and apply the sine of a sum identity. sin 2x = sin (x + x) (Do not simplify.) Use the given information to find (a) sin (s +t), (b) tan (s+t), and (c) the quadrant of s + t. 3 12 and sint=...
Consider the sinusoidal voltage v (t) = 40 cos (100t+60°) V. Part A Part D Part G What is the maximum amplitude of the voltage? Express your answer to three significant figures and include the appropriate units. What is the phase angle in radians? Express your answer in radians to three significant figures. What is the first time after t=0 that v=-40V? Express your answer to three significant figures and include the appropriate units. ? TO AD U veca o...
Consider the equation for the charge on a capacitor in an LRC circuit da + dt2 +79 = E dt which is linear with constant coefficients. , and find the auxiliary equation (using m as your First we will work on solving the corresponding homogeneous equation. Divide through the equation by the coefficient on variable) = 0 which has roots The solutions of the homogeneous equation are Now we are ready to solve the nonhomogeneous equation + 16 + 634...
Question 6 14 pts Consider the curve C defined by the parametric equations: x f(t) y= g(t) = sint -t costt (d) Which picture shows the curve C? Recall the curve C is defined by : x= f(t) cos t g(t) = sint - t y 20 20 10 10F 0 -10 -10 -20 -20 -20 10 -20 10 C 20 -10 0 10 (i) (ii) X 20 20 10 10 0 0 10 -10 -20 -20h -20 10 -20...
2. (Chapter 2). A linear, time-invariant, continuous-time (LTIC) system with input f(t) and output y(t) is specified by the differential equation D2(D +1)y(t) (D - 3)f(t) Find the characteristic polynomial, characteristic equation, characteristic root(s), and characteristic mode(s) of this system. a. b. Is this system asymptotically stable, marginally stable, or unstable? Justify your answer.
2. (Chapter 2). A linear, time-invariant, continuous-time (LTIC) system with input f(t) and output y(t) is specified by the differential equation D2(D +1)y(t) (D - 3)f(t)...
Use the node-voltage method to find the steady-state expression
for io in the circuit seen in (Figure 1) if ig= 6 cos2500tA
and
vg= 20 cos(2500t+90∘)V.
Write the steady-state expression for io(t) as io=Iocos(ωt+ϕ),
where −180∘<ϕ≤180∘.
Assignment 8 Problem 9.56 13 of 19 > Review I Constants Part A Use the node-voltage method to find the steady-state expression ror io in the circuit seen in (Figure 1)T = 6 cos 2500t A and Find the numerical value of 2250090) V...
Chapter 7, Problem 7.014 Use the differential equation approach to find it) for t>0 in the circuit in the figure below. 1 H t=0 iL(t) 3 V 12Ω 6Ω 6Ω 3Ω Please round all numbers to 3 significant digits. Click here to enter or edit your answer L(t) ok