Question

Consider the sinusoidal voltage v (t) = 40 cos (100t+60°) V. Part A Part D Part G What is the maximum amplitude of the voltage? Express your answer to three significant figures and include the appropriate units. What is the phase angle in radians? Express your answer in radians to three significant figures. What is the first time after t=0 that v=-40V? Express your answer to three significant figures and include the appropriate units. ? TO AD U veca o a ? Å Vmax = Value O O Units t= Value Units rad Submit Request Answer Submit Request Answer Submit Request Answer Part 1 Part B Part E The sinusoidal function is shifted 10/3 ms to the right along the time axis. What is the expression for v (t)? What is the frequency in hertz? Express your answer in hertz to three significant figures. What is the phase angle in degrees? Express your answer in degrees to three significant figures. PO AQ U vec OD ? AD U vec mo ? 40 cos(100rt+21/3) V 40 cos(1007) V 40 sin(1007) V 40 sin(100nt +27/3) V Submit Request Answer Submit Request Answer Submit Request Answer Part 1 Part C Part F What is the minimum value of milliseconds that the function must be shifted to the left if the expression for v(t) is 40 sin(100 mt) V? Express your answer in milliseconds to three significant figures. What is the frequency in radians per second? Express your answer in radians per second to three significant figures. What is the period? Express your answer to three significant figures and include the appropriate units IVO A¢ u vec O O ? rad/s Value Units

Answer 1

V(t) = 40 Cos (100 ut +60°)v Part A: Comparing with V(t)= Vracos (wt to) we get Vimax = 400 Part B frequency f= ww = 1001 1 AZ F = 50 Hz Parte: Angular frequency Teo= look rad/s cor) co= 100x 3.14159 radls وعد 159: ہار3 = به 180 Panto: Phase angle o=60 In rad, o= 60 x I o rad 0 = 1.047 rad Past E: In degrees (8= 60° ] o=1.047 rad

Part I: Period T= 1 l To so sec = 0.02 seconds Part G: v(t) = 40 cos (100 + +1.047) -40 = 40 cos Cooñt + l.out) loot +.047 = cos(-4) 100 it + 1.047 = TT looit = 2.095 It = 6.669 msec Part H: 360 = 366 x 7 360 = 211 radians time period is 0.02 For 25 rad sec = rad For 10% ms , angle in radians is (1²) x103 x 25 ñ 0.02 VCZ) = 4pocos (Toont + +). vet) a to cos (100mt + 27%) v

Part I: V(t) as sine function is Ect)= 40 sin(10052 +60 +90 ) V(t)= 40 Sin Coot +150) must be For V(t) = 40sin (1007t) ~, he function Shifted to left by 150. For 3 bo, For iso, Period is 0.02 seconds. t= 150 x 0.02 - seconds. 3b0 1 t= 8.333 ms]