Question

The current and voltage at the terminals of the inductor in the circuit are i(t) = (3.7+3.8e-406) A, t > 0; v(t) = -82e-40 V, t > 0+ (Figure 1) Part A Specify the numerical value of Vs. Express your answer to three significant figures and include the appropriate units. НА, ? V = Value Units Submit Request Answer Part B Specify the numerical value of R. Express your answer to three significant figures and include the appropriate units. HA ? R= Value Units Submit Request Answer Figure < 1 of 1 Part C R Specify the numerical value of Io. Express your answer to three significant figures and include the appropriate units. + V Hile t=0 L 3v1) μΑ een ? I. Value Units

Answer 1

The solution is linked below.

Given that i(t) = (3.7+ 3.80 400) A -40t. V(A) = -82 e for circuit M to + V V[+) 2 We know that at t=0 ilt) = -R/2t (left R. -R/2t and Ulf)= Ee Thus by comparing -yot V (t) = -82e we can say that Ecord Vs = -82 (01) 82 cn opposite direction A TVs: 82V Re: 40 R=40L

Then know We is Energy stored in a inductor i 9 = ('2) 212 9- (1/2) (0-552) (5) 2 9 = 0.277 12 I ²-9/10-277 I ² - 32 = 32.490 I = 5-7A

We know that I = To Cl-ente) 5.7= 3.7(1-e het 1.56=1-6 thus taking in and funding -hot we get that t=0.0154 MS Part & [+= 15.41

Part a Vs=82V. Part B R=22.16ohms.