The inside surface of a glass window (n= 1.5) is coated with a material of n= 1.38. If the surface reflects 570 nm of light back into the room. What is its thickness?
Is the answer : 2d = lambda/n ?? this should be constructive interference. am I wrong?
Yes constructive interference
path difference delta x = 2d ( n ) n = 1.38
for constructive interference delta x = lambda
there fore
2d = lambda/1.38
d = 206.52 nm ( answer )
The inside surface of a glass window (n= 1.5) is coated with a material of n=...
A lens made of glass (n. - 1.52) is coated with a thin film of MgF, (n = 1.38) of thickness t. Visible light is incident normally on the coated lens as in the figure below. Glass thin film Incident An illustration shows a rectangular cross- section of glass lens oriented such that a thin film of thickness tcoats its left side. A ray of light directed to the right is perpendicularly incident upon the left side of the film....
The default setting is a thin film of glass(n = 1.5) with air (n
= 1)on both sides.The starting wavelength is 652 nm and the
starting thickness is 544 nm. Use these starting values for this
next set of questions.
1. Is there a phase shift on the front (left) interface? On the
back (right) interface in the simulation?Justify why there is/isn’t
a phase shift at each interface.
2. How does the wavelength in the film (glass) compare to the...
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Prob. 6b (6 pts.) A glass window is coated with a transparent film of refractive index n2=1.25. This film will cause destructive interference in the reflected light when light of wavelength λ = 550nm. is incident normally,on the window. What is the minimum thickness of film required to produce this anti-reflection coating? incident 1 air fim glass 1.25
I dont understand thin film interference. Thanks in
advance
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