Question

A lens made of glass (n. - 1.52) is coated with a thin film of MgF, (n = 1.38) of thickness t. Visible light is incident norm
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Answer #1

a)

given
refractive index of thin film, n = 1.38
t = 575 nm
If t is the thickness of the layer,

for constructive interference,

the path difference, 2*t = (m + 1/2)*lamda/n (m = 0,1,2,3....) (here n is refractive index of thin film)


for minimum thickness of film, m = 0

2*t = lamda/(2*n)

t = lamda/(4*n)

= 1*593/(4*1.38)

= 107 nm <<<<<<<-------------Answer

b) yes

Explanation :

for m = 1,2,3,4,5,6,....

thickness of film,

t = 321 nm, 535 nm, 749 nm, 963 nm.....

for above thickness of film also 593 nm will be missing.

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