Question

The minimum injection pressure (psi) for injection molding specimens of high amylose corn was determined for eight different specimens (higher pressure corresponds to greater processing difficulty), resulting in the following observations 14.5 12.6 17.8 14,4 12.0 10.5 9.3 8.3 (a) Determine the values of the sample mean X, sample median, and 12.5% trimmed mean Xtr. (Round your answers to two decimal places.) x Compare these values. The mean is much larger than the median and trimmed mean, indicating positive skewness. The median is much larger than the mean and trimmed mean, indicating positive skewness. The median is much larger than the mean and trimmed mean, indicating negative skewness. The mean is much larger than the median and trimmed mean, indicating negative skewness. All three measures of center are similar, indicating little skewness to the data set. (b) By how much could the smallest sample observation, currently 8.3, be increased without affecting the value of the sample median? (c) Suppose we want the values of the sample mean and median when the observations are expressed in kilograms per square Inch (ksi) rather than psi. Is it necessary to reexpress each observation in ksi, or can the values calculated in part (a) be used directly? (Hint: 1 kg -2.2 lb.) Yes, it is necessary to reexpress cach observation. No, the values obtained in part (a) can be used directly.

Answer 1

Tell me what you want to do.... Sign in Home Insert Page Layout Formulas Data Review View Developer Add-ins XLSTAT * Cut Calibri -11 Á A === On Wrap Text General Le Copy Paste BIU, - - A- EE3 Merge & Center - $ % Format Painter , 8 Clipboard Font Alignment Number p x * Autosum · As o Fill Conditional Format as Formatting Table Styles Cell Styles Insert Delete Format - Cells Clear Sort & Find & Filter - Select - Editing M21 for A B C D E F G H I J K L M N O P Q R S T 14.5 12.6 17.8 14.4 12.0 10.6 9.3 8.3 Data 1 8.3 (b) The lowest value 8.3 can be increased upto 3.7 points 9.3 so that it is still lesser or equal to 12 10.6 12.0 12.6 Mean = Median = 12.4 =AVERAGE(C3:13) 12.3 =MEDIAN(C3:13) 14.4 12.5% trimmed mean => removing 12.5% of highest and lowest values 14.5 17.8 14.5 12.6 14.4 12.0 10.6 9.3 c) No, the values calculated in part(a) can be directly used. Trimmed mean = L 12.2|| Compare these values. The mean is much larger than the median and trimmed mean, indicating positive skewness. The median is much larger than the mean and trimmed mean, indicating positive skewness. The median is much larger than the mean and trimmed mean, indicating negative skewness. The mean is much larger than the median and trimmed mean, indicating negative skewness All three measures of center are similar, indicating little skewness to the data set.