If in the following equation , v1 = 0 ft / s; ΔZ = 120 in; P1 = 35 psia; P2 = 14.7 psia, ρ = 62.4 lbm / ft3, the value of v2 would be:
a) 60.5 ft / s
b) 27.1 ft / s
c) 42.7 ft / s
d) 48.7 ft / s
e) 34.3 ft / s
4. Water is to be moved from one large reservoir to another a higher elevation as indicated in the Figure. The flow rate, Q=2 ft/s and the head loss hz = 60 where Vis the average velocity. the pump power required 15000 ft.lb/s. Determine the pump head loss hp. Section (2) p=1.94 slugs/ft3 P2 = P1 = V1 = V2 = 0 8-in. inside diameter pipe 50 Ft P2 + v +24thp = Section (1) Pump P2 vž ==+ +...