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A horizontal spring with stiffness 0.66N/m has a relaxed length of 0.182m. A mass of 0.026kg is attached and you stretch the

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Answer #1

amplitude

A = 0.384 - 0.182 = 0.202 m

velocity at mean position

v = A \sqrt ​​​​​​(k/m)

v = 0.202* \sqrt ( 0.66 / 0.026)

v = 1.018 m/s

=======

Comment before rate in case any doubt, will reply for sure.. goodluck

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