Question

Calculate the force on a door with surface area 1.32 square metres at the International Space Station. Assume the pressure inside the space station is 78.95 kPa and the pressure outside is zero Answer:

Answer 1

Given)

A = 1.32 m²

P = 78.95 Kpa = 78.95 x 10³ Pa

As we know that , the pressure is define as the ratio of the force to the applied perpendicular area.

$P = \frac{F}{A}$

F = PA

F = (78.95 x 10³ Pa)( 1.32 m²)

F = 104214 N

F = 104.2 KN