150.0 mL of 0.23 M HF with 220.0 mL of 0.31 M NaF Calculate the pH of the...

Question

Question

150.0 mL of 0.23 M HF with 220.0 mL of 0.31 M NaF

Calculate the pH of the solution that results from each of the following mixtures.

also, I'm so confused how you get the pKa..... can someone explain that part

Answer 1

Answer #1

pKa of HF=3.17

[HF]=(150*10^-3)*0.23=0.0345M

[NaF]=(220*10^-3)*0.31=0.0682M

pH=pKa+log[NaF]/[HF]=3.17+log(0.0682/0.0345)=3.46

Answer 2

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