pH + pOH = 14
pOH = 14 - 12.193 = 1.807
pOH = - log [OH]
1.807 = - log [OH]
[OH] = 0.015595 M
Ethyl amine is a weak base:
[OH] = (Kb x C)1/2
[OH]2 = (Kb x C)
Kb = [OH]2/C = 0.015595 x 0.015595 x 0.526 = 1.279 x 10-4
In the laboratory, a general chemistry student measured the pH of a 0.526 M aqueous solution...
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