Given light wavelength lambda = 582 nm , slit width d = 0.026 mm
sepration of slit and screen is D = 4.2 m
we know that the central fringe is maximum and with more intensity
12)
the width of the central fringe is W = LAmbda*D/d
W = 582*10^-9*4.2/(0.026*10^-3) m
W = 0.0940 m
Answer is option (a)
13)
3rd dark fringe angle theta = ?
d sin theta = (m*lambda )
0.026*10^-3 sin theta = 3*582*10^-9
solving for theta , theta = 3.85 degrees = 3.9 degrees
answer is opiton (b)
14 ) if frequency increases the fringes would get closer together
answer is option (b)
Light with wavelength 582 nm goes through a single slit of width 0.026 mm and displays...
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