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7=625 Problem 4) (5pts) Light of wavelength 625 nm passes through a single slit of width 0.320 mm and forms a diffraction pat

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Page No. Ang given 1 = 625 nm = 625 X10 m d = 0.320 mm = 0 320x10 m D=8.oom finst dark tringe, so m-1 So asinomi d=0.320mm D[Pago No. Page No. Date 7 distance between central maxima and Ist dark fringe is 0.015625 m y = 15-625 mmThank you

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