Question

A 10° wedge is to be forced under the end B of the 10-lb rod AB. Knowing that the coefficient of static friction is 0.35 between the wedge and the rod and 0.25 between the wedge and the floor, determine the smallest force P required to raise end B of the rod.

1 ft

Answer 1

we can understand with the below attached image.

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Free Body diagram of wodge (Assuming weightless) 1f2 = M2 N2 Balancing 4070 im Rand y direction - x-direction wit - P + H₂ sino + 22 Cos 0 = 0 Mono -P + Masino + H₂NzCaso o - ci w and X- 1. – 1₂ Cos 0 + MzNe sine =0 FBD of Rod AB 180 x 01 c0 x 200 ch 141_, Ng

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Balanding tay que about point A ETA=0 H₂N₂ caso .R=0 u ing Reos45 - x₂ coso. R + زہ Now, here - 0.25 H₂ = 0.35 me 10 lb = 4.54 kg 0-320 Ralft & 0.31m. 0.0 0 0 10°. q. putting vane in & orgh- > N2(0.35 X (05 10°x 0.31 - tos 1oºx 0.31) -- 454898 5 N, 158.7 N =9 putting value in @ = No - N₂ cose & M₂'Ny sino

No - 146.64 nutting vame in o e) P - MIN + Nasino + M₂N₂COSO P = 118.91 N Min. same of P = 118.91 N