Question

Mohammad Ali Saud Said Albahri a) Find the tensions T, and T2 in the two strings (5 Marks) TT Т. 25° 36° 15 kg b) Two bodies move with same momentum. If the ratio of velocities of the two bodies is 4:2, calculate the ratio of their masses. (2 Marks) 00:33

How I can solve this quesions?

Answer 1

Multiple questions posted , so answering only the first question:

a.For equlibrium, horizontal components of tension must cancel each other.

So, T1 cos 25 = T2 cos 36 => T1 = T2 cos 36/(cos 25).........equation 1.

Also, vertically, the tensions must balance the weight of the block.

Vertical component of tension = T1 sin 25+ T2 sin 36

Weight of block = mg, where m is mass and g is gravitational acceleration.

= 15*9.8 = 147 N

So, T1 sin 25+T2 sin36 = 147

=>[T2 cos 36/(cos 25)]*sin25 +T2 sin36 = 147 (using equation 1)

=>T2 (cos36*sin25/cos25 + sin36) = 147

=>T2 *0.965036 =147

=>T2=152.326 N.

So,T1= T2 cos 36/(cos 25) = 152.326 cos 36/(cos 25) = 135.974 N.

So,T1=135.974 N and T2 = 152.326 N.