Question

Part B: Moles, mass, and molar mass (3). Acetaminophen, an analgesic, has the molecular formula CsHoO2N. (a). What is the molar mass of acetaminophen?

Answer 1

Molar mass of e = 12 g Molar mass of H = 1 g Molar mass of o = 16 g Molar mass of N = 124 g therefore Molar mass of c_8 H_9 o_2 N = (8 times 12) + (9 times 1) + (2 times 16) + 14 g = 151 g Moles present = 7.32/151 = 0.098 Grams present = (0.288 times 151) g = 43.488 g