Question


a-slug mass is hung onto a spring, whereupon the spring is stretched 6 in from its natural length. The mass is n started in motion from the equilibrium position with an initial velocity of 4 ft/sec in the upward direction. Find the subsequent motion of the mass, if the force due to air resistance is -2t lb.
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Answer #1

using hook's law

we have k = m g / L

k = 0.5 X 32.17 / 1.280

k = 6.283 sec

the diff equation is

d2x/dt2 + 8 dx/dt + 25 x = 0

then roots are

\lambda1 = 3 i - 4

\lambda2 = -3 i - 4

then

x = e-4t ( C1 cos3t + C2 sin3t )

x ( 0 ) = 0

and

dx(0)/dt = 4

there fore

x = (4/3) e-4t

x \rightarrow 0 , x \rightarrow\oe

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