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These questions are related to the titration of 40.00 mL of a 0.0850 M acetic acid...

These questions are related to the titration of 40.00 mL of a 0.0850 M acetic acid solution with 0.0700 M KOH. Assume that the temperature is 25 oC. The volume of KOH required to reach the equivalence point of the titration is 48.57 mL, the number of mmol of acetate present at the equivalence point is 3.40 mmol, the total volume of the solution at the equivalence point is 88.57 mL and the analytical concentration of acetate ions at the equivalence point is 0.03839 M.

A) What is the pOH at the equivalence point?

B) What is the pH at the equivalence point?

C) What volume of KOH has been added at the half- equivalence point?

D) What is the pH at the half-equivalence point?

Show work please!

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Answer #1


-S Ka acehe acidこ 1.80x10 kh acetate I0 Ka iniha 003839 M 03 839M-n- Solvivg this quadrahe egahon weget )( 4.62-X106 M nt 2 2

D pH at haf quivalente potnt Ka 4 ate fic a ud --lea (1.80 x10-5) H at half eguivalence leatnt .74- :

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