Consider the titration of 151 mL of a 0.210 M solution of caproic acid (Ka =...
Consider the titration of 151 mL of a 0.210 M solution of caproic acid (Ka = 1.3×10-5) with 1.40 M KOH.
How much titrant must be added to reach the equivalence point?
V = _______ mL
How much titrant must be added to reach the half-way
point?
V = ______ mL
What is the pH at the half-way point?
pH =
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Consider the titration of 151 mL of a 0.210 M solution of
caproic acid (Ka =...
Consider a titration of 25.00 mL Chloroacetic Acid solution [ka=1.4x10^-3] with 0.1202 M solution of sodium...
Consider a titration of 25.00 mL Chloroacetic Acid solution [ka=1.4x10^-3] with 0.1202 M solution of sodium hydroxide. The volume of 27.40 mL of NaOH(aq) was needed to reach the equivalence point. Calculate: a) The concentration of the chloroacetic acid solution before the titration b) the pH of the chloroacetic acid solution before titration c) the pH of the solution at half equivalence point d) the pH of the solution at the equivalence point e) the pH of the solution when...
Consider a titration of 250 mL 0.15 M acetic acid (Ka = 1.8 x10-5) with 0.10...
Consider a titration of 250 mL 0.15 M acetic acid (Ka = 1.8 x10-5) with 0.10 M KOH. What is the pH of the acetic acid solution (ie: before the titration has begun?) What is the pH after adding 25 mL of 0.10 M KOH? What is the volume of base needed to reach the equivalence point? Is the pH at equivalence point acidic, basic, or exactly neutral? What is the pH after 500 mL of KOH has been added?
consider the titration of a 34.0 mL sample of a 0.180 M HBr with 0.210 M...
consider the titration of a 34.0 mL sample of a 0.180 M HBr with 0.210 M KOH. determine the following: a. initial pH b. the volume if added base required to reach the equivalence point c. the pH at 10.6 mL of added base d. the pH at the equivalence point e. the pH after adding 5.0 mL of base beyond the equivalence point
Consider the titration of 50.00 mL of a 0.1000 M solution of a weak acid, HA,...
Consider the titration of 50.00 mL of a 0.1000 M solution of a weak acid, HA, with a 0.0900 M solution of the strong base KOH as the titrant. Determine the pH at the equivalence point of this titration. The acid dissociation constant for the acid HA is Ka = 1.78 x 10-4. a. 9.01 b. 8.21 c. 5.79 d. 5.07
Consider a titration of 20.00mL cyanic acid solution (Ka=3.5x10^-4) with 0.1082 M solution of sodium hydroxide....
Consider a titration of 20.00mL cyanic acid solution (Ka=3.5x10^-4) with 0.1082 M solution of sodium hydroxide. The volume of 21.70 mL of NaOH(aq) was needed to reach the equivalence point. Calculate: a) the concentration of the cyanic acid solution before the titration b) the pH of the cyanic acid solution before the titration c) the pH of the solution at half-equivalence point
A student peforms a titration, titrating 25.00 mL of a weak monoprotic acid, HA, with a...
A student peforms a titration, titrating 25.00 mL of a weak monoprotic acid, HA, with a 1.22 M solution of NaOH. They collect data, plot a titration curve and determine the values given in the below table. ml NaOH added pH Half-way Point 18.34 4.06 Equivalence point 36.68 8.84 How many moles of NaOH have been added at the equivalence point? mol What is the total volume of the solution at the equivalence point? mL During the titration the following...
In the titration of a solution of weak monoprotic acid with a 0.1275 M solution of NaOH, the pH h...
In the titration of a solution of weak monoprotic acid with a 0.1275 M solution of NaOH, the pH half way to the equivalence point was 4.48. In the titration of a second solution of the same acid, exactly twice as much of a 0.1275 M solution of NaOH was needed to reach the equivalence point. What was the pH half way to the equivalence point in this titration?
In the titration of a solution of weak monoprotic acid with...
These questions are related to the titration of 40.00 mL of a 0.0850 M acetic acid...
These questions are related to the titration of 40.00 mL of a 0.0850 M acetic acid solution with 0.0700 M KOH. Assume that the temperature is 25 oC. The volume of KOH required to reach the equivalence point of the titration is 48.57 mL, the number of mmol of acetate present at the equivalence point is 3.40 mmol, the total volume of the solution at the equivalence point is 88.57 mL and the analytical concentration of acetate ions at the...
A titration is performed on 50mL of a 0.10 M solution of HN3 (Ka+1.9x10-5) with 0.10...
A titration is performed on 50mL of a 0.10 M solution of HN3 (Ka+1.9x10-5) with 0.10 M NaOH as the titrant. (a) What is the initial pH of the HN3 solution? (b) Calculate the pH of the solution after 25 ml of NaOH have been added (c) How many mL of NaOH are required to reach the equivalence point and what is the pH of the solution at the equivalence point.
The next 9 questions are related to the titration of 20.00 mL of a 0.0700 M...
The next 9 questions are related to the titration of 20.00 mL of a 0.0700 M acetic acid solution with 0.0950 M KOH. What is the initial pH of the analyte solution? What volume of KOH is required to reach the equivalence point of the titration (in mL)? How many mmol of the salt are present at the equivalence point? (ANALYTICAL AMOUNT, NOT EQUILIBRIUM AMOUNT) What is the volume of the solution at the equivalence point (in mL)? What is...
In the titration of a solution of weak monoprotic acid with a 0.1275 M solution of NaOH, the pH half way to the equivalence point was 4.48. In the titration of a second solution of the same acid, exactly twice as much of a 0.1275 M solution of NaOH was needed to reach the equivalence point. What was the pH half way to the equivalence point in this titration?
In the titration of a solution of weak monoprotic acid with...
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