For a disk of radius R = 23 cm and Q = 3 x 10^-6 C,...

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Answer 1

Answer #1

here Area A = pi r^2

A = 3.14 * 0.23 * 0.23 = 0.166 m^2

a. Electric field E = Q/A/2eo *(1 -z/(R^2 + z^2)^1/2

E = (3e -6 /0.166) /(2*8.85 e-12) *(1 - 0.01/(0.23^2 + 0.01^2)^0.5

E = 4.4 *10^6 N/C

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b. E = Q/A/(2e0) *(1-z/R)

E = (3 e-6/0.166) /(2 * 8.85 e -12) * (1- 0.01/0.23)

E = 4.394 e 6 N/C

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c. E = Q/A2eo

E = 3e -6/( 0.166* 2 * 8.85 e -12)

E = 1.021 e 6 N/C

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Answer 2

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