An electron is projected into an electric field at an angle of 125° with respect
to the x-axis with speed 1525 m/s. What is the acceleration of the
electron once it is in the electric field (neglect any
gravitational effects)? You may consider the electron to enter the
field at the origin of coordinates. What is the position of the
electron after 15 s, assuming it remains in the same field for the
whole time?
Full solution please!
electric force, Fe = qE
and a = Fe/m = qE/m
a = (1.6 x 10^-19 x 3.2 ) / (9.109 x 10^-31)
a = 5.62 x 10^11 m/s^2 (along -ve x axis) .....Ans
Applying r = ut + at^2/2
u = 1520 (cos125i + sin125j) = -871.84i + 1245.11j m/s
r = (-871.84i + 1245.11j)(15) + (15^2/2) (- 5.62 x 10^11 i )
r = -13077.6i + 18676.65j - 6.32x10^13i
r = - 6.32 x 10^13i + 18676.65j m
so electrons corrdinates are ( -6.32 x 10^13, 18676.65) m
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