An electron s released from rest in a weak electric field given by E = -1.10...

Question

Question

Answer 1

Answer #1

Net Force is Fnet = Fe+Fg

Fe = q*E = 1.6*10^-19*1.1*10^-10 = 1.76*10^-29 N in Y-direction

Fg = m*g = (9.11*10^-31*9.8) = 89.278*10^-31 N in the -Y-direction

Fnet = (176*10^-31)-(89.278*10^-31) = 86.722*10^-31 N

Work done by the net force = change in kinetic energy

Fnet*S = 0.5*m*v^2

86.722*10^-31*1.9*10^-6 = 0.5*9.11*10^-31*v^2

v = 6.014 mm/s

Answer 2

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