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Electron released in an E-Field An electron is released from rest in a uniform electric field and accelerates to the east at
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Answer #1

Use the Newton’s second law of motion and the value of acceleration to find the electric field magnitude as shown below
F ma q E ma > (16X10-19) E - 9.21x10-32g 125m)52) /N E 11 7.12x10-10

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