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Consider an x distribution with standard deviation 0 - 36. (a) Ir specifications for a research project require the standard
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Giver, M=15 a n=46 I x = M = is 9 = 1.1795356 = 1.18 P(15 EXS 17) - Pl 15-18 PE s 7-17 & 17 - Plocz & 1.695) - P(Z < 1.695)-b) na 58 = 15 My = E F - 1.05045189 - LOS OMS189 z 1.05 Plotsisa) : (* ) a plosza 1.90476) = P(Z 41.90480) P(ZLO) - 0.971597-

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