Question

Consider the electromagnetic waves A and B. If the wavelength for A is 19.2 nm, what is the energy in kJ of wave B? MA MM B S
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Answer #1

Wavelength(A) = (7/2) * Wavelength(B)  ​​​​​​ [From given figure]

Therefore, Wavelength(B) = (2/7) * 19.2 nm = 5.486 nm.

Energy (B) = hc / Wavelength(B)

= (6.63 X 10^(-37) kJ-s) * (3 X 10^8) / 5.486 X 10^(-9) m

= 3.62 X 10^(-20) kJ.

Hence, Option E is the correct answer.

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