Question

(A) Draw the ray diagram to find the approximate location of the image (use the provided sketch and a ruler, you must turn this sheet to be graded with our rays on it). 6.0 cm +-13 cm- Lens 1 Lens 2 Fi F. F. 22 cm 40 cm (B) Find the final image distance as measured from lens 1 to the final image. (C) What is the magnification of this image?

Answer 1

b)

using lens formula

1/f = 1/v - 1/u

1/ 13 = 1/ v + 1/22

v = 31.778 cm

now the above image acts as object for lens2

u' = - ( 40 - 31.778) = - 8.22 cm

using lens formula for lens 2

1/f' = 1/v' - 1/u'

-1/6 = 1/v' + 8.22

v' = - 3.468 cm

distance from lens 1

d = 40 - 3.468 = 36.53 cm

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c)

m = (v/u) (v'/u')

m = 0.6094

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F.