Question

Please draw the ray diagram for me and label correctly using the below data please.

Concave lens

Given information:

• Focal length (f) = -6.0 cm
• Object distance (s₀) = 10.0 cm
• Object height (h₀) = 4.0 cm

Perform calculations to determine the quantities in the table below. Please show all work.

Parameter	Calculation Result
Image distance (si)	15.0 cm
Image height (hi)	6.0 cm
Image type	Virtual
Magnification	1.5

Answer 1

Given object distance, $o=10cm$

focal length, $f=-6cm$

For concave lens use negative focal length.

Use lens formula $\frac{1}{f}=\frac{1}{o}+\frac{1}{i}$

$-\frac{1}{6cm}=\frac{1}{10cm}+\frac{1}{i}$

$-\frac{1}{6}=\frac{1}{10}+\frac{1}{i}$

$-\frac{1}{6}-\frac{1}{10}=\frac{1}{i}$

$\frac{-10-6}{10*6}=\frac{1}{i}$

$\frac{-16}{10*6}=\frac{1}{i}$

$-\frac{10*6}{16}=i$

ANSWER: ${\color{Red} i=-3.75cm}$

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Magnification

$M=\frac{h_{i}}{h_{o}}=-\frac{i}{o}$

$M=-\frac{-3.75cm}{10cm}$

ANSWER: ${\color{Red} M=0.375}$

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$M=\frac{h_{i}}{h_{o}}=-\frac{i}{o}$

$\frac{h_{i}}{4cm}=-\frac{-3.75cm}{10cm}$

$h_{i}=\frac{3.75*4}{10}$

ANSWER: ${\color{Red} h_{i}=1.5cm}$

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Image type: Real and upright

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f Image object