draw a ray diagram for this
If a virtual image is formed along the principal axis 10.0 cm from a concave mirror with the focal length 15.0 cm, what is the object distance from the mirror?
Use the mirror equation:
1/di + 1/do = 1/f
where di = -10 cm and f = +15 cm. (Note that di is negative if the image is virtual.)
Substitute and solve for do.
1/do + 1/(-10 cm) = 1/(15 cm)
1/do = 1/(15 cm) - 1/(-10 cm) = 5/(30 cm)
do = 6 cm
draw a ray diagram for this If a virtual image is formed along the principal axis...
draw a ray diagram for this A concave mirror with a focal length of 10.0 cm creates a real image 30.0 cm away on its principal axis; the corresponding object is located how far from the mirror? Use the mirror equation: 1/di + 1/do = 1/f where di = +30 cm and f = +10 cm. Substitute and solve for do. 1/do + 1/(30 cm) = 1/(10 cm) 1/do = 1/(10 cm) - 1/(30 cm) = 2/(30 cm) do =...
draw a ray diagram for this please let (Ashif Ansari) to draw it he is vary good at it A concave mirror with a focal length of 10.0 cm creates a real image 30.0 cm away on its principal axis; the corresponding object is located how far from the mirror? Use the mirror equation: 1/di + 1/do = 1/f where di = +30 cm and f = +10 cm. Substitute and solve for do. 1/do + 1/(30 cm) = 1/(10...
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Please draw the ray diagram for me and label correctly using the
below data please.
Concave lens
Given information:
Focal length (f) = -6.0 cm
Object distance (s0) = 10.0 cm
Object height (h0) = 4.0 cm
Perform calculations to determine the quantities in the table
below. Please show all work.
Parameter
Calculation Result
Image distance (si)
15.0 cm
Image height (hi)
6.0 cm
Image type
Virtual
Magnification
1.5
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