Question

draw a ray diagram for this please let (Ashif Ansari) to draw it he is vary...

draw a ray diagram for this please let (Ashif Ansari) to draw it he is vary good at it  

A concave mirror with a focal length of 10.0 cm creates a real image 30.0 cm away on its principal axis; the corresponding object is located how far from the mirror?

Use the mirror equation:

1/di + 1/do = 1/f

where di = +30 cm and f = +10 cm.

Substitute and solve for do.

1/do + 1/(30 cm) = 1/(10 cm)

1/do = 1/(10 cm) - 1/(30 cm) = 2/(30 cm)

do = 15 cm

0 0
Add a comment Improve this question Transcribed image text
Answer #1

bet k obiect distance be l-e Image distance focal length of Using + + t = 1 V=-30 cm concave mirror fa-10cm to 130 + - IO 30-Thanks Please rate it up.

Add a comment
Know the answer?
Add Answer to:
draw a ray diagram for this please let (Ashif Ansari) to draw it he is vary...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • draw a ray diagram for this A concave mirror with a focal length of 10.0 cm...

    draw a ray diagram for this A concave mirror with a focal length of 10.0 cm creates a real image 30.0 cm away on its principal axis; the corresponding object is located how far from the mirror? Use the mirror equation: 1/di + 1/do = 1/f where di = +30 cm and f = +10 cm. Substitute and solve for do. 1/do + 1/(30 cm) = 1/(10 cm) 1/do = 1/(10 cm) - 1/(30 cm) = 2/(30 cm) do =...

  • draw a ray diagram for this If a virtual image is formed along the principal axis...

    draw a ray diagram for this If a virtual image is formed along the principal axis 10.0 cm from a concave mirror with the focal length 15.0 cm, what is the object distance from the mirror? Use the mirror equation: 1/di + 1/do = 1/f where di = -10 cm and f = +15 cm. (Note that di is negative if the image is virtual.) Substitute and solve for do. 1/do + 1/(-10 cm) = 1/(15 cm) 1/do = 1/(15...

  • You stand two feet away from a planer mirror. How far is it from you to...

    You stand two feet away from a planer mirror. How far is it from you to your image? a. 2.0 ft b. 3.0 ft C. 4.0 ft. d. 5.0 ft. 10. A concave mirror forms a real image 25.0 cm from the mirror surface along the principal axis. If the corresponding object is at a 10.0-cm distance, what is the mirror's focal length? a. 1.43 cm b. 16.7 cm c. 12.4 cm d. 7.14 cm 11. If a virtual image...

  • PHYS 203 Name: Ray Tracing Name: Work in pairs. Turn in one copy per pair Part A: Ray Tracing (18 pts) For each of the following situations, draw the three principle rays and find the image. M...

    PHYS 203 Name: Ray Tracing Name: Work in pairs. Turn in one copy per pair Part A: Ray Tracing (18 pts) For each of the following situations, draw the three principle rays and find the image. Measure, f.p. q. h and h and label them below (1 "large box" 1.0 cm). Indicate whether the image is: - real or virtual upright or inverted - enlarged or reduced - in front or behind the mirrorlens No pens allowed. Draw this in...

  • Used scaled ray tracing for the following scenarios and find the distance to the image, whether...

    Used scaled ray tracing for the following scenarios and find the distance to the image, whether the image is upright or inverted, and whether the image is larger or smaller than the object. a. An object is 30 in front of a concave mirror with a focal length of 10 . b. An object is 14 in front of a concave mirror with a focal length of 20 . c. An object is 70 in front of a convex mirror...

  • Please draw the ray diagram for me and label correctly using the below data please. Concave...

    Please draw the ray diagram for me and label correctly using the below data please. Concave lens Given information: Focal length (f) = -6.0 cm Object distance (s0) = 10.0 cm Object height (h0) = 4.0 cm Perform calculations to determine the quantities in the table below. Please show all work. Parameter Calculation Result Image distance (si) 15.0 cm Image height (hi) 6.0 cm Image type Virtual Magnification 1.5

  • ASAP, Two plane mirrors make the angle a = 26.0° between them. A ray of light...

    ASAP, Two plane mirrors make the angle a = 26.0° between them. A ray of light incident on one of the mirrors is reflected and it hits the second mirror. Find the angle between the ray incident on the first mirror and the ray reflected off of the second mirror. CE A 23.0 cm tall cup is placed 83.1 cm away from the center of a concave mirror with a focal length of 37.0 cm. What is the height of...

  • Please help with number 4 please I'm so lost Use a ray diagram to determine the...

    Please help with number 4 please I'm so lost Use a ray diagram to determine the location of the image for the following problem: an object is placed 15 mm away from a concave mirror with a focal length of 10 mm. Use the mirror formula to check your diagram Use a ray diagram to determine the location of the image for the following problem: an object is placed 15 mm in front of a convex mirror and an image...

  • A 0 cm tall object is placed 10 cm away from a concave mirror that has...

    A 0 cm tall object is placed 10 cm away from a concave mirror that has a 4.0 cm focal length. Calculate the: Image distance Image Height Magnification A 1.0 cm tall object is placed 5 cm away from a biconcave lens that has a 10.0 cm focal length. Calculate the: Image distance Image Height Magnification Using the optics as configured in #5 & #6, Draw a ray-tracing diagram, with all principle rays. What is the nature of the image?

  • For the following question, draw a ray diagram for each lens draw a careful and accurate...

    For the following question, draw a ray diagram for each lens draw a careful and accurate ray diagram of this image (from lens 1) as an object (for lens 2) forming an image through the second lens. Finally, draw a careful and accurate ray diagram of the entire situation, including both lenses and all images. An object 5 cm high is located 75 cm from a converging lens (X1 = 75 cm) of focal length f1 = 50 cm. A...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT