What is the pH of NH4C2H3O2 given information below?
HC2H3O2⇌H+ + C2H3O2- Ka=1.76*10^-5 pKa=4.75
NH3+H2O⇌NH4+ + OH- Kb=1.79*10^-5 pKb=4.75
Assume initial concentration of NH4C2H3O2 is 0.100 M
Use quadratic formula if necessary
What is the pH of NH4C2H3O2 given information below? HC2H3O2⇌H+ + C2H3O2- Ka=1.76*10^-5 pKa=4.75 NH3+H2O⇌NH4+ +...
Important Info: Ka reaction: HC2H3O2(aq) + H2O(l) <-->C2H3O2 (aq) +H3O+(aq) HC2H3O(aq) +OH-(aq) -> C2H3O2-(aq) + H2O (l) A 1.0 L buffer solution is 0.280 M in HC2H302 (acetic acid) and 0.320 M in NaC2H302 (sodium acetate). Calculate the pH of the budder and he Ka for HC2H3O2 IS 1.8 X 10-5 Calculate the pH of te solution above after the addition of 0.0400 moles of solid NaOH. Assume no volume change upon the addition of base.
onsider the reaction of NH3 with water: NH3 + H2O ↔ NH4+ + OH- (Kb=Kw/Ka) and also NH4+ + H2O ↔ NH3 + H3O+ (Ka = 5.70×10-10) be sure to show all work including the ICE Tables. a) Find the pH of 50.00 mL of 0.200M NH3 after the addition of 45.00 mL of 0.200M HCl. b) Find the pH of 50.00 mL of 0.200M NH3 after the addition of 50.00 mL of 0.200M HCl. c) Find the pH of...
Calculate Ka for 1 M NaCH3COO pH = 9.37 H+ = 4.203 X 10^-10 OH- = 2.402 X 10^-5 CH3COO- = 1.00 X 10^0 CH3COOH = 2.402 X 10^-5 ________________ Calculate Ka using the formula Kw = Ka X Kb and the appropriate equilibrium constant for 1 M NaCH3COO. NaCH3COO ---> Na+ (neutral) + CH3COO-. Is the conjugate base for CH3COOH. CH3COOH Ka1 = 1.8 X 10^-5 ______________________ Calculate Ka for 1 M NH4Cl pH = 4.26 H+ = 2.336...
1. Calculate the concentration of H3O+ for an aqueous solution with a pH of 1.2 A) 6.3 x 10-7M B ) 1.6 x 108 M. C) 1.0 x 10-14 M. D) 6.20 x 10-2 M E) 4.0 x 10-4M 2. Calculate the concentration of OH- for an aqueous solution with a pH of 13.8. A) 0.64 M B) 4.0 x 10-5M C) 1.5 x 10-5M D) 1.0 x 10-14 M E) 2.5 x 10-10 M 3. Which of the following...
Ammonia react with water as shown in the following equation: NH3(aq) + H2O(l) NH4+(aq) + OH-(aq) Kb = 1.77 x 10-5 and Ka = 5.65 x 10-10 a) Calculate the pH of the 0.030 M NH3 solution (Use a labeled ICE table) b) Calculate the pH of the solution at the equivalent point (when equal amount of acid is added. Assume the volume doubles). (Use a labeled ICE table) c) Over which pH range (actual numbers) do you expect...
At the equivalence point of a titration of HOAc (acetic acid, pKa = 1.76 x 10-5) with NaOH, the species present of OAc" and H20. If the concentration of OAc at the equivalence point is 0.50 M, what is the pH of the solution? Remember that Kb x Ka = 10-14 and that the OAc will react with water as follows: OAC- + H20 --> HOÀc + OH- . 1 4.77 2. 10.23 3 5.68 4. 9.23
3) Kb for NH3 1.8 x 10-5 a) Calculate the pH of a buffer solution that is 0.100 M NH3 and 0.120 M NHANO3. b) What is the pH after 60.0 mL of 0.010 M HCl is added to 90.0 mL of the buffer solution in 2(a). Assume the change in volume is additive. c) What is the pH after 60.0 mL of 0.010 M Ca(OH)2 is added to 90.0 mL of the buffer solution in 2(a). Assume the change...
Question 10 0/5 points A buffer solution is made such that the initial concentrations of lactic acid (HC3H5O3) and the lactate ion (C3H503) are both 0.600 M. What is the resulting pH if 0.020 mol of hydrochloric acid is added to 0.500 L of the buffer solution? (The Ky of HC3H5O3 is 1.4 x 10" 4.) HINT: Use your RICE chart! [A-] Note: pH = pka + log [HA] Ka x Ky = Kw = 1.0 x 10-14 2.92 3.80...
4.13 Just as pH is the negative logarithm of [H3O+], pKa is the negative logarithm of Ka, pKa=−logKa The Henderson-Hasselbalch equation is used to calculate the pH of buffer solutions: pH=pKa+log[base][acid] Notice that the pH of a buffer has a value close to the pKa of the acid, differing only by the logarithm of the concentration ratio [base]/[acid]. Part B How many grams of dry NH4Cl need to be added to 2.10 L of a 0.400 M solution of ammonia,...
The equlibrium constant for the equation NH3(aq) + H2O(l) ↔ NH4+(aq) + OH⁻(aq) is Kb= 1.8×10-5 at 25 ºC. Calculate ΔGºrxn at 25 ºC. a) -2.27 kj/mol b) 0 kj/mol c) 2.27 kj/mol d) 267 J/mol 27.1 kj/mol