Find a Fourier series to x - x²
from x = -π to x = π
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1. Find the complex Fourier series of the following f(x) = x, -π < x < π
Find the Fourier series of f on the given interval.
f(x) =
0,
−π < x < 0
x2,
0 ≤ x < π
Find the Fourier series of f on the given interval. So, -< x < 0 <x< N F(x) = COS nx + sin nx n = 1 eBook
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Find the Fourier series of the given function (a) f(x) = 1, -π < x < π (b) f(x)= { 0, -2< x <0 ; 2x 0 ≤ x < 2(c) f(x) = { -x -1, -1 < x <0 ; 1 - x, 0 ≤ x < 1
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