Question

Current I =514 flows through a large conductor illustrated below. If r;=1m and r2=2m and the resistivity of the conductor is

0 0
Add a comment Improve this question Transcribed image text
Answer #1

E,= Sx I = 2x 10 NI .= ī 112 ar2 I Ele for za sveta 10 Ez = By the = 2x sem eyesha Mke = { NIL Answer (6) Ez= lx īr2 = 2x 51

Add a comment
Know the answer?
Add Answer to:
Current I =514 flows through a large conductor illustrated below. If r;=1m and r2=2m and the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • question 2,7,9 please Charge 1. (10 points) What is the current through a conductor if X...

    question 2,7,9 please Charge 1. (10 points) What is the current through a conductor if X electrons pass through a cross section in Y time? 2. (10 points) The current flowing through a conductor is X. If it flows for Y time, how many electrons is that X = 100 microamps, Y = 2 days 3. (10 points) A current XuA flows and Y electrons are transported. How long did it take? Resistivity 4. (10 points) An object is round...

  • Water flows through a pipe as shown below. A1 and A2 have equal radii of r1=r2=.05...

    Water flows through a pipe as shown below. A1 and A2 have equal radii of r1=r2=.05 m. A3 has a radius r3=.15 m. The section of the pipe between A1 and A2 is made that it has an unknown cross sectional area. The initial velocity of the fluid and pressure of the fluid and pressure at location 1 is 10 m/s and 6.01x10^5 N/m^2 respectively. (Water has a density of 1000 kg/m^3 also treat the water as ideal i.e. negligible...

  • I wanna know how to solve theses.. professor.. 8. Inside a perfect conductor, there is no...

    I wanna know how to solve theses.. professor.. 8. Inside a perfect conductor, there is no electric field, i.e., E =0.(20) a. Show that the electrostatic potential is constant in the surface of the conductor. (5) b. Show that the electric field just outside the conductor is perpendicular to its surface. (5) c. There is a hollow (vacuum) cavity lying inside a conductor. What is the electric field in the hollow volume? (10) 9. There is an infinitely long solenoid...

  • PLEASE ANSWER ALL OF THE QUESTIONS Question 1 1 pts Each of three objects has a...

    PLEASE ANSWER ALL OF THE QUESTIONS Question 1 1 pts Each of three objects has a net charge. Objects A and B repel each other. Objects B and C attract each other. Which one of the following table entries is a possible combination of the signs of the net charges on these three objects? A B с (1) + + - + (2) + + (3) (4) - (5) + - 0 1) 3) 0 (3) and (5) O (1)...

  • SULIT (ЕКТ 242) 7- (СА, СОЗ, РО2) (c) The semicircular conductor with radius, r 2 m...

    SULIT (ЕКТ 242) 7- (СА, СОЗ, РО2) (c) The semicircular conductor with radius, r 2 m is shown in Figure 3 lies on the x- y plane and carries current I 32 A. The closed circuit is exposed to a uniform magnetic field, B -14. Calculate the following: [Pengalir separa bulatan dengan jejari, r 2 m ditunjukkan dalam Rajah 3 terletak di atas satah x-y dan membawa arus I-32 A. Litar tertutup tersebut terdedah kepada medan magnet seragam, B-14. Tentukan...

  • Please write the python functions Problem: Electric wire (Figure is a cylindrical conductor covered by an...

    Please write the python functions Problem: Electric wire (Figure is a cylindrical conductor covered by an insulating material. Figure 2 shows the structure ofa single conductor. The resistance of a piece ofwire is given by the formula: A d where ρ is the resistivity of the conductor, and I (in meter), A, and d (in meter) are the length, cross-sectional area, and diameter of the wire. The wire diameter, d, is commonly specified by the American Wire Gauge (AWG). Which...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT